如何在typedef结构中使用const int？

类似的东西：当你第一次创建它时，你可以设置它的常量值，而不是之后，因为它将在程序内存中。程序内存不能以这种方式改变。



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Something like this:
typedef struct{
char const * const Name[2];
const int MaxValue;
const int Type;
const int EppromLocation;
const int NextID;
const int PreviousID;
} Parameters_t;
Parameters_t Parameter={ {{"abc"},{"def"}},1,2,3,4,5};

You can set the constant value when you first create it but not after since it will be in program memory. Program memory cannot be changed in that way.

搜索：编译时间vs运行时。要添加：如果你正在修改它，那么它不能是常数。你可以指向一个常量内存，比如一个字符串。现在删除const直到它工作。如果它是一个数组，那么你仍然可以把它全部设置成一个，就像我之前的几篇文章。



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Search: compile time vs runtime.

To add:
If you are modifying it then it can not be constant. You can point to constant memory such as a string.
Remove the const for now until it is working.

If it is an array then you still can set it all up in one like I did a few posts ago.

谢谢你的快速回复。如果我想在源文件中使用多个寄存器呢？源文件出错



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Thank you for quick reply. What if i want to use multiple registers in source file?
Header
typedef struct{
char const * const Name[2];
const int MaxValue;
const int Type;
const int EppromLocation;
const int NextID;
const int PreviousID;
} Parameters_t;
Parameters_t Parameter[5];

In source file
Parameters_t MenuRegister[5];

void RegisterInit()
{

MenuRegister[0]={{{"abc"},{"def"}},1,2,3,4,5};
}

I'm getting error

a.c:17: error: (195) expression syntax
a.c:17: error: (312) ";" expected
a.c:17: error: (285) no identifier in declaration
a.c:17: warning: (374) missing basic type; int assumed

此语法只能用于初始化，而不应用于赋值。它需要成为宣言的一部分。



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This syntax can only be used in initialization, not in an assignment. It needs to be part of the declaration.

该结构将不会放置在程序内存中。这不是永久的。



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That structure will not be placed in program memory. It is not const.

你必须在编译时设置数组/Stutt。你仍然在使用常量运行时。你可以这样做一个数组：PosialPyt p [3 ]＝{{“abc”，“DEF”}，1，2，3，4，5 }，{“GHI”，“JKL”}，6，7，8，9，10 }，{{“MNO”，“PQR”}，11，12，13，14，15}；



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You have to set the array/struct at compile time.
You are still using runtime on constants.


You can do an array like this:
Parameter_t p[3]=
{
{{"abc","def"},1,2,3,4,5},
{{"ghi","jkl"},6,7,8,9,10},
{{"mno","pqr"},11,12,13,14,15}
};

设置一次，忘记一次。



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Set once and forget.

如果你这样改变你的结构，它们都是conist.Type，const结构{{}；在常量内存中：



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If you change your structure heading like this, they are all then constants.
typedef const struct{};


In constant memory:
const Parameter_t p[3]=
{
{{"abc","def"},1,2,3,4,5},
{{"ghi","jkl"},6,7,8,9,10},
{{"mno","pqr"},11,12,13,14,15}
};

大括号改变范围。



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Curly braces change the scope.

放入程序存储器：



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To place into program memory:
typedef const struct {
const char *Name[2];
int MaxValue;
int Type;
int EppromLocation;
int NextID;
int PreviousID;
} Parameters_t;

Parameters_t Parameter[5] = {
{{"abc","def"},1,2,3,4,5},
{{"ghi","jkl"},6,7,8,9,0},
{{"mno","pqr"},1,2,3,4,5},
{{"stu","vwx"},6,7,8,9,0},
{{"foo","bar"},1,2,3,4,5}
};

很好的回答谢谢！第一个问题我可以宣布它们是秘密的。原因是我想读取每个变量名来理解它所做的每件事。例如：等等。它帮助我读取变量名。第二个问题，我可以用不同的寄存器吗？最后一个问题，如果我将包含在一个非静态的值示例中，我会在初始化中一起声明它们吗？



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Nice answer thanks! First question can i declare them separetaly. The reason is that i want to read each variable name for understanding what everything its doing.

Example:


Parameters_t Parameter[1].Name = {"abc","def"};

and so on.It Helps me to read variable name.
Second question can i use different registers for each one?

Parameters_t Parameter[1] = { {{"abc","def"},1,2,3,4,5};
Parameters_t Parameter[2] = { {{"abc","def"},1,2,3,4,5};
Parameters_t Parameter[3] = { {{"abc","def"},1,2,3,4,5};


And last qustion, what if i i will include inside a non static value example

typedef const struct {
const char *Name[2];
int MaxValue;
int Type;
int EppromLocation;
int NextID;
int PreviousID;
union
{
unsigned int Value;
unsigned char bytes[2];
}SetValues;

} Parameters_t;


Can i declare them together in initialize?

作为声明的一部分，您只能将整个结构初始化一次。你不能把它拆开。我不知道你的意思是“把它们一起声明为初始化”。



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You can only initialize the entire structure one time as part of the declaration. You can't split it up. I don't know what you mean by "declare them together in initialize".

它可以帮助我一起读取变量，以便于如果需要更改，示例：所以我需要并列放置const和unconst变量。



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It helps me to read variables all together, for make it easy if i need to make a change;
Example:
Register[0].PreviousID=2;
Register[0].Name[0]="AAAAA";
Register[0].Name[1]="asdwwew";
Register[0].MaxValue=100;
Register[0].MinValue=0;
Register[0].SetValues.Value=10;
Register[0].NextID=1;

So i need to place const and non const variables side by side.

如果需要，可以在结构中混合const和unconst成员。但是在const成员中设置一个值的唯一方法是声明它。



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You can mix const and non-const members in a struct if you want. But the only way to set a value in a const member is when it's declared.

我认为这里有一个失败来掌握初始化代码和可执行代码之间的区别。



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I think there is a failure here to grasp the difference between initialisation code and executable code.

那么，QusiTo是，当它们被声明时，我可以设置它们两者的值（const和const）吗？const值也应该在数组内吗？我可以用变量的名字来区分它们吗？就像我的例子一样，我如何在相同的Type结构中使用const和unconst？



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Ok then the qustion is can i set values both of them (const and non const)when they are declared?

Also const values should be inside an array? Can i separate them with the name of its variable? like my example.
Also how i will use const and non const inside same typedef struct?