printf with uint32_t给出了奇怪的错误消息

我尝试了你在主C中写的代码。
UIT32 32 VAR＝0x000 023；
CyGloalActuabess；/*启用全局中断。*/
PrtTf（“%LU”，var）；
但是我没有在PSoC创建者4.1 UpDeDe1中有任何错误指示器（屏幕截图）。
你能提供你观察这个问题的项目吗？
PNG
69.4 K



以下为原文
I tried what you mentioned by writing this code in main.c-
uint32_t var=0x00023;
CyGlobalIntEnable; /* Enable global interrupts. */
printf("%lu",var );
But I didn't got any error indicator ( screenshot attached ) in PSoC Creator4.1 update1.
Can you please provide the project in which you are observing the issue.

• Capture.PNG69.4 K
  
  

嗨，Anks，
你错过了包括和。请尝试包含这个文件。我附上了行为的截图，一个是%u，一个是%u，重建后拍摄照片。
当做，
拉尔夫
Test-Primtf Unt32×T.2.PNG
25.9 K
Test-Primtf Unt32×Typ1.PNG
25.4 K



以下为原文
Hi Anks,

you missed to include . Please try it with including this file. I attached screenshots of the behaviour, one with %u and one with %lu, pictures are taken after rebuild.

Regards,

Ralf

• Test_Printf uint32_t #2.png25.9 K
  
  
• Test_Printf uint32_t #1.png25.4 K
  
  

尝试使用UIT32而不是UIT32 32，您不应该看到任何警告。



以下为原文
Try using uint32instead of uint32_t, you should not see any warnings.

嗨，SRDS，
谢谢，我会试试看。因此，这个问题是因为IDE不能确定PrtTF参数的UIT32 32位的位宽度吗？
当做



以下为原文
Hi srds,

thank you, I'll try it. So, this issue is because the IDE is not capable of determining the bit width of uint32_t for the printf arguments?

Regards

注意，它是代码编辑器中的诊断警告（因为Type是不同的）而不是编译器生成的警告。因此，UIT32和UIT32的功能都是相同的。



以下为原文
Note that it is a diagnostic warning in the code editor (since the typedef are different) and not a compiler generated warning. So, both uint32 and uint32_t functionally work the same way.

即使是UIT32，我在编辑器中得到警告，从%LU更改为%u，但是如果我这样做，编译器就会发出警告。



以下为原文
even with uint32 i am getting warning in editor to change to %u from %lu, but if i do that then compiler gives warning.

如果你正在使用PSoC 6 MCU，试试这个：
Prtf（“Val:%Lurn”），（未签名long）Val.



以下为原文
If you are using PSoC 6 MCU, try this:

printf("Value of Val: %lurn", (unsigned long)Val);