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STM32串口DMA发送数据不连续

3603 STM32 串口

问答对人有帮助，内容完整，我也想知道答案 0 STM32串口DMA发送的数据不连续，已经试了一些办法，仍未解决，不知是什么原因？用串口监控得到的数据是： 10,9:07:54,io.exe(5532),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 12,9:07:54,io.exe(5532),IRP_MJ_READ,COM8,1, 4D \| M, 13,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 00 \| #0, 14,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 01 \| #1, 15,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 23 \| #, 16,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 00 \| #0, 17,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 03 \| #3, 18,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 5C \| , 19,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 88 \| ?, 20,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 00 \| #0, 21,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 13 \| #19, 22,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, CB \| ?, 23,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 12 \| #18, 24,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 00 \| #0, 25,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 00 \| #0, 26,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 90 \| ?, 27,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, D2 \| ò, 28,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 07 \| #7, 29,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, EE \| ?, 30,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 17 \| , 31,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, E1 \| á, 32,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 00 \| #0, 33,9:07:56,io.exe(5532),IRP_MJ_READ,COM8,1, 0D \| #13, 0
2019-2-14 06:42:44　　评论淘帖0 邀请回答您可以邀请以下用户，快速回答问题 × richthoffen 该类别下有 182 个回答。邀请回答 7vyydyfwef 该类别下有 57 个回答。邀请回答我是卖报的小男孩该类别下有 32 个回答，其中被选为最佳答案 1 次。邀请回答 chenbingjy 该类别下有 31 个回答。邀请回答谦谦三君子该类别下有 27 个回答。邀请回答短短该类别下有 25 个回答。邀请回答 YY599566 该类别下有 22 个回答。邀请回答 dingyang598 该类别下有 22 个回答，其中被选为最佳答案 1 次。邀请回答 nvuuweew 该类别下有 22 个回答。邀请回答 h1654155957.9572 该类别下有 19 个回答。邀请回答 60user16 该类别下有 19 个回答。邀请回答 hapyy 该类别下有 19 个回答。邀请回答 HEHELA 该类别下有 18 个回答。邀请回答 DerSohn 该类别下有 18 个回答。邀请回答 huhu12 该类别下有 18 个回答。邀请回答陈军该类别下有 15 个回答。邀请回答 csz9981 该类别下有 15 个回答。邀请回答天地直方该类别下有 15 个回答。邀请回答 dull20112011 该类别下有 15 个回答。邀请回答 proyeah 该类别下有 14 个回答。邀请回答举报张云相关推荐 • 为什么STM32串口DMA连续发送两个数据依旧会丢失呢 2105 • STM32串口DMA连续发送两帧导致数据部分覆盖怎么解决？ 1659 • STM32串口DMA数据不能发送怎么解决？？ 1132 • 如何解决STM32串口＋DMA发送数据程序卡死问题？ 2965 • STM32串口dma发送数据部分字节出错得原因？如何解决？ 2579 • 如何知道STM32串口使用DMA方式完成了数据的接收呢 2362 • stm32串口发送数据个数和上位机接收到的数据个数不匹配怎么办? 1414 • 通过STM32串口向PC串口软件不停的发送数据怎么终止接收？ 3052 • STM32串口+DMA怎么使用？ 863 • 如何解决STM32 UART4串口4连续发送数据丢失部分数据问题？ 1183 12个回答

答案对人有帮助，有参考价值 0

2019-2-14 06:56:41 评论举报张云

答案对人有帮助，有参考价值 0 看不懂你贴这段数据是什么意思，你至少应该说明你用了什么型号的芯片，那个串口，是DMA直接发送还是DMA中断发送，如果可能的话，最好贴上出问题的工程代码，这样懂的人想帮助你的人才能更好的帮你解决问题。

2019-2-14 07:01:48 评论举报张倩

答案对人有帮助，有参考价值 0 帮顶

2019-2-14 07:08:36 评论举报黄敏

答案对人有帮助，有参考价值 0 同意2楼，不知道这是什么，帮顶

2019-2-14 07:13:55 评论举报任娟娟

答案对人有帮助，有参考价值 0 USART串口通讯的代码如下： void GPIO_Configuration(void) { GPIO_InitTypeDef GPIO_InitStructure; RCC_APB2PeriphClockCmd(RCC_APB2Periph_GPIOA \| RCC_APB2Periph_GPIOB \| RCC_APB2Periph_AFIO, ENABLE); RCC_APB2PeriphClockCmd(RCC_APB2Periph_USART1, ENABLE); GPIO_InitStructure.GPIO_Pin = GPIO_Pin_9; GPIO_InitStructure.GPIO_Mode = GPIO_Mode_AF_PP; GPIO_InitStructure.GPIO_Speed = GPIO_Speed_50MHz; GPIO_Init(GPIOA, &GPIO_InitStructure); GPIO_InitStructure.GPIO_Pin = GPIO_Pin_10; GPIO_InitStructure.GPIO_Mode = GPIO_Mode_IN_FLOATING; GPIO_Init(GPIOA, &GPIO_InitStructure); } //串口初始化： void USART_Configuration(void) { USART_InitTypeDef USART_InitStructure; USART_InitStructure.USART_BaudRate = 9600; USART_InitStructure.USART_WordLength = USART_WordLength_8b; USART_InitStructure.USART_StopBits = USART_StopBits_1; USART_InitStructure.USART_Parity = USART_Parity_No; USART_InitStructure.USART_HardwareFlowControl = USART_HardwareFlowControl_None; USART_InitStructure.USART_Mode = USART_Mode_Rx \| USART_Mode_Tx; USART_Init(USART1, &USART_InitStructure); USART_ITConfig(USART1, USART_IT_IDLE , ENABLE); USART_Cmd(USART1, ENABLE); USART_ClearFlag(USART1, USART_FLAG_TC); // 清发送完成标志 } //DMA配置： void DMA_Configuration(void) { DMA_InitTypeDef DMA_InitStructure; RCC_AHBPeriphClockCmd(RCC_AHBPeriph_DMA1, ENABLE);//DMA1时钟 DMA_DeInit(DMA1_Channel4); DMA_InitStructure.DMA_PeripheralBaseAddr = 0x40013804; DMA_InitStructure.DMA_MemoryBaseAddr = (u32)TX1_SendBuf; DMA_InitStructure.DMA_DIR = DMA_DIR_PeripheralDST; //外设作为DMA的目的端 DMA_InitStructure.DMA_BufferSize = 512; // 根据实际发送数据长度确定 DMA_InitStructure.DMA_PeripheralInc = DMA_PeripheralInc_Disable; //外设地址不增加 DMA_InitStructure.DMA_MemoryInc = DMA_MemoryInc_Enable; //内存地址自增1 DMA_InitStructure.DMA_PeripheralDataSize = DMA_PeripheralDataSize_Byte; DMA_InitStructure.DMA_MemoryDataSize = DMA_MemoryDataSize_Byte; DMA_InitStructure.DMA_Mode = DMA_Mode_Normal;//（只传送一次） DMA_Mode_Circular; DMA_InitStructure.DMA_Priority = DMA_Priority_VeryHigh; //DMA传送优先级 DMA_InitStructure.DMA_M2M = DMA_M2M_Disable; DMA_Init(DMA1_Channel4, &DMA_InitStructure); DMA_ITConfig(DMA1_Channel4, DMA_IT_TC, ENABLE); DMA_ITConfig(DMA1_Channel4, DMA_IT_TE, ENABLE); USART_DMACmd(USART1, USART_DMAReq_Tx, ENABLE); DMA_Cmd(DMA1_Channel4, DISABLE); DMA_DeInit(DMA1_Channel5); DMA_InitStructure.DMA_PeripheralBaseAddr = 0x40013804; DMA_InitStructure.DMA_MemoryBaseAddr = (u32)RX1_RcvBuf; DMA_InitStructure.DMA_DIR = DMA_DIR_PeripheralSRC; DMA_InitStructure.DMA_BufferSize = 512; DMA_InitStructure.DMA_PeripheralInc = DMA_PeripheralInc_Disable; DMA_InitStructure.DMA_MemoryInc = DMA_MemoryInc_Enable; DMA_InitStructure.DMA_PeripheralDataSize = DMA_PeripheralDataSize_Byte; DMA_InitStructure.DMA_MemoryDataSize = DMA_MemoryDataSize_Byte; DMA_InitStructure.DMA_Mode = DMA_Mode_Normal;//（只传送一次） DMA_InitStructure.DMA_Priority = DMA_Priority_VeryHigh; //DMA传送优先级 DMA_InitStructure.DMA_M2M = DMA_M2M_Disable; DMA_Init(DMA1_Channel5, &DMA_InitStructure); DMA_ITConfig(DMA1_Channel5, DMA_IT_TC, ENABLE); DMA_ITConfig(DMA1_Channel5, DMA_IT_TE, ENABLE); USART_DMACmd(USART1, USART_DMAReq_Rx, ENABLE); DMA_Cmd(DMA1_Channel5, ENABLE); } //中断优先级配置： void NVIC_Configuration(void) { NVIC_InitTypeDef NVIC_InitStructure; /* Configure one bit for preemption priority / NVIC_PriorityGroupConfig(NVIC_PriorityGroup_2); //中断分组设置 / Enable the USART1 Interrupt / NVIC_InitStructure.NVIC_IRQChannel = USART1_IRQn; //设置串口1中断 NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 1; //抢占优先级 NVIC_InitStructure.NVIC_IRQChannelSubPriority = 2; //响应优先级 NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE; NVIC_Init(&NVIC_InitStructure); / Enable the USART2 Interrupt */ NVIC_InitStructure.NVIC_IRQChannel = USART2_IRQn; NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 2; NVIC_InitStructure.NVIC_IRQChannelSubPriority = 2; NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE; NVIC_Init(&NVIC_InitStructure); NVIC_InitStructure.NVIC_IRQChannel = DMA1_Channel4_IRQn; NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 1; //抢占优先级 1 NVIC_InitStructure.NVIC_IRQChannelSubPriority = 0; //响应优先级 NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE; NVIC_Init(&NVIC_InitStructure); NVIC_InitStructure.NVIC_IRQChannel = DMA1_Channel5_IRQn; NVIC_InitStructure.NVIC_IRQChannelPreemptionPriority = 1; //抢占优先级 NVIC_InitStructure.NVIC_IRQChannelSubPriority = 1; //响应优先级 NVIC_InitStructure.NVIC_IRQChannelCmd = ENABLE; NVIC_Init(&NVIC_InitStructure); } void USART1_IRQHandler(void) //USART1收发全用DMA { u16 DATA_LEN; if(USART_GetITStatus(USART1, USART_IT_IDLE) != RESET)//如果为空闲总线中断 { DMA_Cmd(DMA1_Channel5, DISABLE); if(RX1_dataOverflow == 0) //1=接收的数据超过缓冲区数量 { DATA_LEN = 512 - DMA_GetCurrDataCounter(DMA1_Channel5); //已经传输的字节数 if(RX1_RcvBuf[0] == 'M')//;判断是否为帧头，MODBUS数据接收标志，0x4D='M' { RX1_Data_Len = DATA_LEN; Handle_MODBUS_CMD(); } else if(RX1_RcvBuf[0] == 126)//检查USART1的国军标协议接收标志，为1则有命令帧需处理 { HandleCMD() ; } } RX1_dataOverflow = 0; //1=接收的数据超过缓冲区数量 DMA_ClearFlag(DMA1_FLAG_GL5 \| DMA1_FLAG_TC5 \| DMA1_FLAG_TE5 \| DMA1_FLAG_HT5);//清标志 DMA1_Channel5->CNDTR = 512;//重装填 DMA_Cmd(DMA1_Channel5, ENABLE);//处理完,重开DMA DATA_LEN = USART1->SR; DATA_LEN = USART1->DR; } if(USART_GetITStatus(USART1, USART_IT_PE \| USART_IT_FE \| USART_IT_NE) != RESET)//出错 { USART_ClearITPendingBit(USART1, USART_IT_PE \| USART_IT_FE \| USART_IT_NE); } USART_ClearITPendingBit(USART1, USART_IT_TC); USART_ClearITPendingBit(USART1, USART_IT_IDLE); }

2019-2-14 07:25:06 评论举报张云

答案对人有帮助，有参考价值 0 用其它单片机与PC软件通讯，监测到的数据如下，这是正确的，单片机串口发送数据无间断：序号,时间,进程(PID),IO类型,COM口,数据长度,数据, 74,10:49:20,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 75,10:49:20,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CC 00 13 C7 7B 00 00 90 B1 06 AB 17 E0 00 05 06 AB 42 F4 0D 9D 42 03 AB 6F 24 14 75 00 01 00 03 0A 80 \| M#0#2##0#3[ì#0#19?{#0#0?±#6?à#0#5#6?B?#13?B#3?o$u#0#1#0#3#10?, 76,10:49:22,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 77,10:49:22,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B D4 00 13 C7 CB 00 00 90 AA 0A 27 17 E0 00 18 07 BB 42 F2 C0 81 42 00 7F 15 22 27 72 00 01 00 03 0A 8E \| M#0#1##0#3[?#0#19??#0#0?a#10'à#0#7?Bòà?B#0"'r#0#1#0#3#10?, 78,10:49:22,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 79,10:49:22,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CC 00 13 C7 7D 00 00 90 B1 06 B7 17 E0 00 05 06 B7 42 F4 0F BC 42 03 AD F2 24 14 B0 00 01 00 03 0B 7B \| M#0#2##0#3[ì#0#19?}#0#0?±#6·à#0#5#6·B?#15?B#3-ò$°#0#1#0#3#11{, 80,10:49:24,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 81,10:49:24,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B D5 00 13 C7 CE 00 00 90 AB 0A 20 17 E0 00 18 07 BB 42 F2 BF 30 42 00 7D 87 22 27 4E 00 01 00 03 0A 86 \| M#0#1##0#3[?#0#19??#0#0??#10 à#0#7?Bò?0B#0}?"'N#0#1#0#3#10?, 82,10:49:26,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 83,10:49:26,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CD 00 13 C7 80 00 00 90 B1 06 CF 17 E0 00 05 06 CF 42 F4 14 09 42 03 B3 09 24 15 28 00 01 00 03 09 97 \| M#0#2##0#3[í#0#19??#0#0?±#6?à#0#5#6?B?#9B#33#9$(#0#1#0#3#9?, 84,10:49:26,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 85,10:49:26,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B D6 00 13 C7 D0 00 00 90 AB 0A 14 17 E0 00 18 07 BB 42 F2 BD 11 42 00 7B 04 22 27 13 00 01 00 03 09 9C \| M#0#1##0#3[?#0#19?D#0#0??#10à#0#7?Bò?#17B#0{#4"'#19#0#1#0#3#9?, 86,10:49:28,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 87,10:49:28,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CD 00 13 C7 82 00 00 90 B1 06 E6 17 E0 00 06 06 E6 42 F4 18 52 42 03 B8 1B 24 15 9E 00 01 00 03 0A A2 \| M#0#2##0#3[í#0#19??#0#0?±#6?à#0#6#6?B?RB#3?$?#0#1#0#3#10￠, 88,10:49:30,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 89,10:49:30,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B D7 00 13 C7 D3 00 00 90 AB 09 FC 17 E0 00 18 07 BB 42 F2 B8 C4 42 00 75 ED 22 26 9B 00 01 00 03 0C 9F \| M#0#1##0#3[×#0#19?ó#0#0??#9üà#0#7?Bò??B#0uí"&?#0#1#0#3#12?, 90,10:49:30,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 91,10:49:30,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CE 00 13 C7 85 00 00 90 B1 07 0D 17 E0 00 07 07 0D 42 F4 1F 5B 42 03 C0 6D 24 16 61 00 01 00 03 09 25 \| M#0#2##0#3[?#0#19??#0#0?±#7#13à#0#7#7#13B?[B#3àm$a#0#1#0#3#9%, 92,10:49:32,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 93,10:49:32,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B D8 00 13 C7 D5 00 00 90 AB 09 E5 17 E0 00 17 07 BB 42 F2 B4 7B 42 00 70 DB 22 26 25 00 01 00 03 0B B0 \| M#0#1##0#3[?#0#19??#0#0??#9?à#0#7?Bò′{B#0p?"&%#0#1#0#3#11°, 94,10:49:34,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 95,10:49:34,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CF 00 13 C7 88 00 00 90 B2 07 3C 17 E0 00 08 07 3C 42 F4 27 C5 42 03 CA 62 24 17 4B 00 01 00 03 09 E5 \| M#0#2##0#3[?#0#19??#0#0?2#7<à#0#8#7 96,10:49:34,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 97,10:49:34,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B D9 00 13 C7 D8 00 00 90 AC 09 BE 17 E0 00 16 07 BB 42 F2 AD 72 42 00 68 89 22 25 62 00 01 00 03 0B 5F \| M#0#1##0#3[ù#0#19??#0#0??#9?à#0#7?Bò-rB#0h?"%b#0#1#0#3#11_, 98,10:49:36,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 99,10:49:36,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B CF 00 13 C7 8A 00 00 90 B2 07 64 17 E0 00 08 07 64 42 F4 2E E5 42 03 D2 CF 24 18 10 00 01 00 03 0A 99 \| M#0#2##0#3[?#0#19??#0#0?2#7dà#0#8#7dB?.?B#3ò?$#16#0#1#0#3#10?, 100,10:49:38,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 01 01 06 00 08 \| M#0#1#1#6#0#8, 101,10:49:38,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 01 23 00 03 5B DA 00 13 C7 DB 00 00 90 AC 09 8F 17 E0 00 15 07 BB 42 F2 A5 07 42 00 5E 94 22 24 78 00 01 00 03 0A D6 \| M#0#1##0#3[ú#0#19??#0#0??#9?à#0#7?Bò￥#7B#0^?"$x#0#1#0#3#10?, 102,10:49:38,KCJC_Set.exe(2228),IRP_MJ_WRITE,COM8,7, 4D 00 02 01 06 00 09 \| M#0#2#1#6#0#9, 103,10:49:38,KCJC_Set.exe(2228),IRP_MJ_READ,COM8,41, 4D 00 02 23 00 03 5B D0 00 13 C7 8D 00 00 90 B2 07 9E 17 E0 00 0A 07 9E 42 F4 39 52 42 03 DF 26 24 19 32 00 01 00 03 0A 12 \| M#0#2##0#3[D#0#19??#0#0?2#7?à#0#10#7?B?9RB#3?&$2#0#1#0#3#10#18,

2019-2-14 07:42:41 评论举报张云

答案对人有帮助，有参考价值 0 用STM32F103C8，运行前面的程序代码时，STM32F103C8串口用DMA收发数据，发出的数据流不连续，有间断，像这样： 19,14:00:30,io.exe(3252),IRP_MJ_WRITE,COM8,7, 4D 00 02 03 06 00 0B \| M#0#2#3#6#0#11, 21,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 4D \| M, 22,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 23,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 02 \| #2, 24,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 15 \| , 25,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, D3 \| ó, 26,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, EE \| ?, 27,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, CD \| í, 28,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, A8 \| ¨, 29,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, BF \| ?, 30,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, CD \| í, 31,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, B3 \| 3, 32,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, B5 \| μ, 33,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 34,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 35,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 36,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 37,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 38,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 39,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 40,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 41,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 42,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 43,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 44,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 45,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 00 \| #0, 46,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 06 \| #6, 47,14:00:30,io.exe(3252),IRP_MJ_READ,COM8,1, 8E \| ?,

2019-2-14 08:00:57 评论举报张云

答案对人有帮助，有参考价值 0 像是一个一个发出的，不知是什么原因？请高手帮助分析一下，谢谢。

2019-2-14 08:12:29 评论举报张云

答案对人有帮助，有参考价值 0 帮顶

2019-2-14 08:28:13 评论举报华农武

答案对人有帮助，有参考价值 0 顶一个，，，，

2019-2-14 08:45:04 评论举报董薇

答案对人有帮助，有参考价值 0 楼主，这个问题有解决吗？我的也是这个问题，折腾了2天了没有搞定呀

2019-2-14 08:56:32 评论举报王敏

答案对人有帮助，有参考价值 0 USART串口通讯的代码如下：

2019-2-14 09:11:59 评论举报张桂芝

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