[问答]

无法在INT2引脚上产生中断

问答对人有帮助，内容完整，我也想知道答案 0 我无法在INT2引脚上产生中断。但我可以在INT1引脚上生成具有相同配置的中断。好像我错过了一些明显的东西，或者数据表缺少一些关键的东西！我试图从Z轴检测180度翻转。在平坦的表面上，Z轴向上指向我约+ 1g（十进制65，FS = 2）。 180翻转会给我一个负值。这是在INT1引脚上工作的配置。 CTRL_REG1 = 0x5F // ODR = 100Hz，LPen = 1，所有轴启用CTRL_REG2 = 0x42 //参考过滤，中断2上AOI功能的过滤数据 REFERENCE = 50 //将z轴值接近15 CTRL_REG3 = 0x20 // INT1上的IA2中断 CTRL_REG5 = 0x08 //对于INT1的锁存 CTRL_REG6 = 0 INT2_THS = 100 // 180度翻转让我大约-112，参考50 INT2_DURAtiON = 50 // 500ms，ODR = 100Hz INT2_CFG = 0x20 // Z轴上的高电平中断使能通过上述配置，我可以检测到INT1引脚上的中断。对于INT2引脚我改变了， CTRL_REG3 = 0 CTRL_REG5 = 0x02 // INT2的锁存 CTRL_REG6 = 0x20 // INT2引脚上的IA2中断 ......我没有收到任何打扰。我只是重定向了引脚。这应该工作。除非我遗漏了一些明显的东西。任何帮助都感激不尽。 #accelerometer #mems #interrupt 以上来自于谷歌翻译以下为原文 I am unable to generate an interrupt on INT2 pin. But I can generate an interrupt with the same configuration on INT1 pin. Seems like I am missing something obvious or the datasheet is missing something crucial!! I am trying to detect a 180-degree flip from Z-axis. On a flat surface, Z-axis pointing upwards gives me approx +1g (decimal 65 with FS = 2). 180 flip will give me a negative value. Here is the configuration that worked on INT1 pin. CTRL_REG1 = 0x5F // ODR = 100Hz, LPen = 1, All axis enabled CTRL_REG2 = 0x42 // Reference filtering, Filter data for AOI function on interrupt 2 REFERENCE = 50 // Taking the z-axis value close to 15 CTRL_REG3 = 0x20 // IA2 interrupt on INT1 CTRL_REG5 = 0x08 // Latch for INT1 CTRL_REG6 = 0 INT2_THS = 100 // A 180-degree flip gives me around -112 with REFERENCE 50 INT2_DURATION = 50 // 500ms with ODR=100Hz INT2_CFG = 0x20 // Interrupt enable for High on Z-axis With above configuration, I can detect the interrupt on INT1 pin. For INT2 pin I changed, CTRL_REG3 = 0 CTRL_REG5 = 0x02 // Latch for INT2 CTRL_REG6 = 0x20 // IA2 interrupt on INT2 pin ...and I don't receive any interrupt. I just redirected the pin. This should work. Unless I am missing something obvious. Any help will be much appreciated. #accelerometer #mems #interrupt 0
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答案对人有帮助，有参考价值 0 你的配置是正确的，它正在工作，但我看到一个小问题可能会造成麻烦。在第一种情况下，当中断指向INT1引脚时，进行设置 CTRL_REG5 = 0x08，此配置设置中断发生器1的锁存模式，而不是引脚INT1。并且因为您正在使用中断发生器2，所以不使用此设置，并且中断未被锁存（返回0，电路板被翻转回来）。当您将中断指向INT2时，设置CTRL_REG5 = 0x02，此配置设置中断发生器2的锁存模式。当您使用此中断发生器时，INT2凹坑保持高电平，直到您读取INT2_SRC寄存器为止。我尝试了两种情况，并且按照您的预期触发了中断，但在第二种情况下，我必须读取INT2_SRC寄存器以清除中断。以上来自于谷歌翻译以下为原文 You configuration is correct and it is working, but I see one small issue which probably makes the troubles. In the first case when the interrupt is directed to INT1 pin, you set CTRL_REG5 = 0x08, this configuration set the Latch mode for the interrupt generator 1 not for the pin INT1. And because you are using interrupt generator 2 this settings is not used and the interrupt is not latched (returns back to 0 wen the boards is flipped back). When you direct the interrupt to INT2 you set CTRL_REG5 = 0x02, this configuration set the Latch mode for interrupt generator 2. As you are using this interrupt generator, the INT2 pit remains high until you read INT2_SRC register. I tried both case and the interrupt is triggered as you would expect but in second case I have to read the INT2_SRC register to clear the interrupt.

2019-4-16 13:50:47 评论举报曾玲娟

答案对人有帮助，有参考价值 0 我懂了。这就说得通了。让我试试你的建议。以上来自于谷歌翻译以下为原文 I see. That makes sense. Let me try your suggestion.

2019-4-16 14:04:47 评论举报李蒙