[问答]

怎么让MCC ADC1与PIC32MM配合使用

问答对人有帮助，内容完整，我也想知道答案 0 我正试图通过PIC32 MM000 64 GPL036获得12频道的ADC。由MCC生成的相关代码是：TyPulfStruts {Unt8It t ItStase}；ADCYObjor；静态ADCI对象ADC1OOBJ；/*部分：驱动接口/Office ADC1x初始化（空隙）{//ASAM禁用；完成禁用；形成整型16位；SAMP禁用；SSRC清除采样位结束采样并启动转换。on；SIDL禁用；MODE12＝0x8000；//CSCNA禁用；BFFM禁用；SMPI 1；OFFACK禁用；VCFG AVDD/AVSS；BFRIGEN禁用；AD1CON2= 0x0；/SAMC 0；EXRSAM禁用；ADRC FRC；ADC 0；AD1CON3= 0x8000；//CH0SAN AN0；CH0NA AVSS；AD1CHS＝0X0；//CSS9禁用；CSS6禁用；CSS3禁用；CSS2禁用；CSS1禁用；CSS13禁用；CSS12禁用；CSS11禁用；CSS10禁用；CSS30禁用；CSS29禁用；CS128禁用；AD1CSS= 0x0；/CHH9禁用；CHH8禁用；CHH7禁用；CHH7；CHH7禁用；CSH28禁用；CSH28禁用；禁用CHH6；CHH3禁用；CHH2禁用；CHH0禁用；CHH10禁用；CHH13禁用；CHH12禁用；AD1CHIT＝0x0；ADC1YObj.ItStase= AD1CON2BITS.SMPI；}空隙ADC1SART启动（空隙）{AD1CON1BITS。SAMP＝1；}空ADC1-停止（VoI）（0）；Unt161t ADC1OxFuffelGET（UtiN16T缓冲器）{INTUC16TADC16PTR；ADC16PTR=（UINT16T）和（ADC1BUF0）；（计数＝0；计数＝ADC1OOB.int采样；计数+++）{缓冲器[CUT] =（UINT16YT）ADC16PTR；ADC16PTR++；}返回计数；} UINT1616T ADC1L转换d）{1}1位SultGET（空）{返回ADC1BUF0；}布尔ADC1IIS转换完成（空隙）{返回AD1CON1BITS。完成；和/或等待转换完成}空隙ADC1Chhannel选择（ADC1-信道）{Ad1CHS＝通道；}空ADC1任务（空隙）{/ /清除ADC中断标志IFS0ClR＝1 & lt；/*文件结束 /我不确定函数需要调用什么顺序来进行转换。我现在使用的主循环是：（1）{int回答；int信道＝12；ADC1a信道选择（通道）；ADC1a启动（）；Adc1AsExchange完全（））；Adc1IsStor（）；回答= ADC1OxExchange结果（）；}使用调试器，我陷入了while语句中。从阅读数据表，我无法确定我需要做什么来获得转换。来自PIC18，似乎更复杂。任何帮助都非常感谢。谢谢。以上来自于百度翻译以下为原文 I'm trying to get the ADC working on channel 12 with the PIC32MM0064GPL036. The pertinent code generated by MCC is: typedef struct { uint8_t intSample; } ADC_OBJECT; static ADC_OBJECT adc1_obj; /** Section: Driver Interface / void ADC1_Initialize (void) { // ASAM disabled; DONE disabled; FORM Integer 16-bit; SAMP disabled; SSRC Clearing sample bit ends sampling and starts conversion; SIDL disabled; MODE12 10-bit; ON enabled; AD1CON1 = 0x8000; // CSCNA disabled; BUFM disabled; SMPI 1; OFFCAL disabled; VCFG AVDD/AVSS; BUFREGEN disabled; AD1CON2 = 0x0; // SAMC 0; EXTSAM disabled; ADRC FRC; ADCS 0; AD1CON3 = 0x8000; // CH0SA AN0; CH0NA AVSS; AD1CHS = 0x0; // CSS9 disabled; CSS8 disabled; CSS7 disabled; CSS6 disabled; CSS5 disabled; CSS4 disabled; CSS3 disabled; CSS2 disabled; CSS1 disabled; CSS0 disabled; CSS13 disabled; CSS12 disabled; CSS11 disabled; CSS10 disabled; CSS30 disabled; CSS29 disabled; CSS28 disabled; AD1CSS = 0x0; // CHH9 disabled; CHH8 disabled; CHH7 disabled; CHH6 disabled; CHH5 disabled; CHH4 disabled; CHH3 disabled; CHH2 disabled; CHH1 disabled; CHH0 disabled; CHH11 disabled; CHH10 disabled; CHH13 disabled; CHH12 disabled; AD1CHIT = 0x0; adc1_obj.intSample = AD1CON2bits.SMPI; } void ADC1_Start(void) { AD1CON1bits.SAMP = 1; } void ADC1_Stop(void) { AD1CON1bits.SAMP = 0; } uint16_t ADC1_ConversionResultBufferGet(uint16_t buffer) { int count; uint16_t ADC16Ptr; ADC16Ptr = (uint16_t )&(ADC1BUF0); for(count=0;count<=adc1_obj.intSample;count++) { buffer[count] = (uint16_t)ADC16Ptr; ADC16Ptr++; } return count; } uint16_t ADC1_ConversionResultGet(void) { return ADC1BUF0; } bool ADC1_IsConversionComplete( void ) { return AD1CON1bits.DONE; //Wait for conversion to complete } void ADC1_ChannelSelect( ADC1_CHANNEL channel ) { AD1CHS = channel; } void ADC1_Tasks ( void ) { // clear the ADC interrupt flag IFS0CLR= 1 << _IFS0_AD1IF_POSITION; } /* End of File */ I'm unsure of in what order the functions need to be called in to make a conversion. The main loop I am using now is: while(1) { int answer; int channel = 12; ADC1_ChannelSelect(channel); ADC1_Start(); while(!ADC1_IsConversionComplete()) ; ADC1_Stop(); answer = ADC1_ConversionResultGet(); } using the debugger, I am getting caught up in the while statement. From reading the datasheet I am unable to determine what is needed for me to do to get the conversion. Coming from PIC18, it seems much more complicated. Any help is greatly appreciated. Thanks. 0
2019-5-13 09:47:48　　评论淘帖0 邀请回答您可以邀请以下用户，快速回答问题 × qun333 该类别下有 57 个回答。邀请回答技术发广告该类别下有 56 个回答。邀请回答 caoguiqun 该类别下有 56 个回答。邀请回答 psw30 该类别下有 44 个回答。邀请回答伊丹姿子该类别下有 41 个回答。邀请回答 uwufwjrw 该类别下有 39 个回答。邀请回答 hetao1111 该类别下有 38 个回答。邀请回答 lc123617 该类别下有 35 个回答。邀请回答欧阳大大该类别下有 32 个回答。邀请回答作死不止该类别下有 31 个回答。邀请回答 asd010 该类别下有 31 个回答。邀请回答 wy8719 该类别下有 29 个回答。邀请回答 60user92 该类别下有 29 个回答。邀请回答 haikitty 该类别下有 28 个回答。邀请回答 ju978779 该类别下有 28 个回答。邀请回答嘻嘻爱哈哈该类别下有 28 个回答。邀请回答 xiuzhen122 该类别下有 27 个回答。邀请回答 pol666 该类别下有 27 个回答。邀请回答 ueywyrsdfs 该类别下有 26 个回答。邀请回答 lhly23 该类别下有 25 个回答。邀请回答举报陈嘉宁相关推荐 • PIC32MM UART错误中断问题 892 • PIC32MM UART消耗的功率是什么？ 896 • 如何使用PIC32 MM000 64 GPL02020引脚QFN和MPLAB与MCC？ 1492 • 如何在PIC32MM中写入/读取int数字或字符并在加电时重新加载？ 1002 • USB Lite Pic32MM CDC Windows 10未知设备 2198 • 请问PIC32 mm的软替换（）是否正确替换？ 1158 • 编写PIC32MM系列的引导加载程序找不到任何源文件 2806 • MCC引脚分配PIC32MM0256GPM028错误 2034 • PIC32MM编程规范问题 1896 • STM32F407双ADC采样ADC1和ADC2的时钟同时打开ADC1不能工作 4944 1个回答

答案对人有帮助，有参考价值 0 谢谢你的回复。我能让模块按照你的建议工作。我和你有一个相同的问题，但是发现错误是转换时钟被卡在1位（我在1023位或0位被卡在10位模式下）。在我的情况下，它产生了一个可靠的结果。4，我还必须使用PBCK作为源而不是FRC。以上来自于百度翻译以下为原文 Thanks for your reply. I was able to get the module working roughly following what you suggested. I had the same issue as you for a bit, but found the error was that the conversion clock was stuck as 1 TCY (I was stuck at either 1023 or 0 in 10 bit mode). In my case, it was > 4 TCY that produced a reliable result. I also had to use the PBCLK as a source instead of FRC.

2019-5-13 10:12:45 评论举报陆兰兰